From sssjjjnnn@comcast.net:

I noticed some strange behavior in gcc. The following code:

void myfunc() {
  (volatile unsigned)0x8000 = 0;
}

Compiles to:

clr -32767
clr -32768
rtc

It seems that the compiler is converting a 2-byte volatile access into two
1-byte accesses, which is probably not a good idea. The command line I used
to compile is:

m6811-elf-g++.exe -S -mshort -m68hcs12 -fomit-frame -pointer -fno-rtti
-frename-registers -mlong-calls -O2 x.cc

Is there a way to tell the compiler that you want to do a 2-byte access,
e.g. with a movw?

-- Justin